The reaction of 1-naphthyl-methyl-amine and hydro-chloric acid in a 1:1 molar ratio resulted in the formation of the 1:1 proton-transfer compound, C(11)H(12)N(+)·Cl(-). In the crystal, the ions are linked by N-H⋯Cl hydrogen bonds into a sheet pattern in the ab plane such that each Cl(-) ion is bonded to three NH groups from the naphthylmethylammonium ion.