A DNA fragment that carried the genes coding for FokI endonuclease and methylase was cloned from the chromosomal DNA of Flavobacterium okeanokoites, and the coding regions were assigned to the nucleotide sequence by deletion analysis. The methylase gene was 1,941 base pairs (bp) long, corresponding to a protein of 647 amino acid residues (Mr = 75,622), and the endonuclease gene was 1,749 bp long, corresponding to a protein of 583 amino acid residues (Mr = 66,216). The assignment of the methylase gene was further confirmed by analysis of the N-terminal amino acid sequence. The endonuclease gene was downstream from the methylase gene in the same orientation, separated by 69 bp. The promoter site, which could be recognized by Escherichia coli RNA polymerase, was upstream from the methylase gene, and the sequences adhering to the ribosome-binding sequence were identified in front of the respective genes. Analysis of the gene products expressed in E. coli cells by gel filtration and sodium dodecyl sulfate-polyacrylamide gel electrophoresis indicated that the molecular weights of both enzymes coincided well with the values estimated from the nucleotide sequences, and that the monomeric forms were catalytically active. No significant similarity was found between the sequences of the two enzymes. Sequence comparison with other related enzymes indicated that FokI methylase contained two copies of a segment of tetra-amino acids which is characteristic of adenine-specific methylase.